Elcut2ednFelissches
Elcut2ednFelissches Elcut2ednFelissches
  • 24-12-2016
  • Mathematics
contestada

In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and
m∠COD = 16°, what is m∠CED?

37
48
53
62

Respuesta :

nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 26-12-2016
m∠CED = 1/2(m∠AOB + m∠COD) = 1/2(90° + 16°) = 1/2(106°) = 53°

Answer Link
nateodwyer602 nateodwyer602
  • 21-05-2021

Answer:

53

Step-by-step explanation:

Answer Link

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