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22-12-2016
Chemistry

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A voltaic cell that uses the reaction
PdCl2−4(aq)+Cd(s)→Pd(s)+4Cl−(aq)+Cd2+(aq) has a measured standard cell potential of +1.03 V
What is the half-cell cathode reaction?

Respuesta :

johnkellock johnkellock

22-12-2016

Did you intend to write [PdCl4]^-2 instead of PdCl2-4? If so, then:

Cathode: [PdCl4]^-2(aq) + 2e- ======⇒ Pd(s) + 4Cl-(aq)

Anode: Cd(s) ==⇒ Cd+2(aq) + 2e-

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