reynanishanthini03 reynanishanthini03
  • 22-09-2021
  • Mathematics
contestada

2. The length of a rectangle is 5 cm more than its width. If the perimeter of the rectangle is 40cm, find the area of the rectangle.​

Respuesta :

rlesandisusanya
rlesandisusanya rlesandisusanya
  • 23-09-2021

Answer:

area of the rectangle =

[tex] {93.75cm}^{2} [/tex]

Step-by-step explanation:

width = x cm

length = x + 5 cm

Perimeter = 2(length + width)

[tex]p = 2(x + (x + 5)) \\ 40 = 2(x + x + 5) \\ 40 = 2(2x + 5) \\ 40 = 4x + 10 \\ 40 - 10 = 4x \\ 30 = 4x \\ \frac{30}{4} = x \\ 7.5 = x[/tex]

width = 7.5cm

length = 7.5 + 5 = 12.5cm

Area of the rectangle = length × width

[tex]a = 12.5cm \times 7.5 cm\\ a = 93.75 {cm}^{2} [/tex]

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