Answer:
see explanation
Step-by-step explanation:
note that [tex]3^{p+1}[/tex] = [tex]3^{p}[/tex] × 3 ( when multiplying exponents are added )
Given
[tex]\frac{3^{p+1}-3^{p} }{2.3^{p} }[/tex] ← factor out [tex]3^{p}[/tex] on numerator
= [tex]\frac{3^{p}(3-1) }{2.3^{p} }[/tex]
= [tex]\frac{2.3^{p} }{2.3^{p} }[/tex]
= 1
