Answer:
[tex]\frac{\sqrt{47}}{10}[/tex]
Step-by-step explanation:
First you find the missing side using the Pythagorean theorem of [tex]a^{2} +b^{2} =c^{2}[/tex].
Which is [tex](\sqrt{53})^{2} + b^{2} = 10^{2}[/tex].
do the squares to make it 53 + [tex]b^{2}[/tex] = 100 and solve for b.
[tex]b^{2} = 100-53\\b^{2} = 47\\b= \sqrt{47}[/tex]
Sine of an angle is Opposite over Hypotenuse to get
[tex]\frac{\sqrt{47} }{10}[/tex]
