[tex]\huge{ \mathfrak{ \underline{ Answer \: \: ✓ }}}[/tex]
The Angle formed by an arc on the centre of the circle is double the angle made by the same arc on the circumference of the circle.
So,
[tex] \boxed{ \mathrm{ \angle TDB = \dfrac{1}{2} \angle TPB }}[/tex]
- [tex] \mathrm{\angle TDB = \dfrac{1}{2} \times 90 \degree}[/tex]
- [tex] \mathrm{\angle TDB =45 \degree } [/tex]
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