Answer:
[tex]2x + 3y = 6 ---(1)\\y = \frac{x}{6} - 3 ----(2)\\\\substitute \ y \ in \ (1)\\2x + 3(\frac{x}{6} - 3) = 6\\\\2x + \frac{x}{2} - 9 = 6\\\\\frac{5x}{2} = 6+9\\\\\frac{5x}{2} = 15\\5x = 30 \\x = 6\\substitute \ x \ in \ (2)\\\\y = \frac{6}{6} -3 = 1 - 3= -2[/tex]
x = 6, y = -2
