Answer:
consider a right angle triangle. ∠A = 90° , ∠B = [tex]\theta[/tex]
[tex]Sin\theta = \frac{6}{7} => AC = 6, BC = 7 \\\\BC^2 = AB^2 + AC^2 \\\\49 = 36 + AB^2 \\\\AB = \sqrt{13} \\\\Tan \theta = \frac{opposite}{adjacent } = \frac{6}{\sqrt{13} }[/tex]
