Answer:
[tex]-2\pm i\sqrt{5}[/tex]
Step-by-step explanation:
[tex]x^2-6x+12=-10x+3\\x^2+4x+9=0[/tex]
For the quadratic formula, [tex]a=1,\,b=4,\,c=9[/tex].
[tex]\frac{-b \pm\sqrt{b^2-4ac}}{2a}=\frac{-4\pm\sqrt{16-4(1)(9)}}{2(1)}=\frac{-4\pm\sqrt{-20}}{2}\\=\frac{-4\pm 2\sqrt{-5}}{2}=-2\pm\sqrt{-5}=-2\pm i\sqrt{5}[/tex]
