Seudónimo Seudónimo
  • 22-05-2021
  • Mathematics
contestada

Factorise fully [tex]3y^{3} -12y[/tex]

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Аноним Аноним
  • 22-05-2021

Answer:

[tex] {3y}^{3} - 12y \\ = 3y( {y}^{2} - 4) \\ = 3y( {y}^{2} - {2}^{2} ) \\ = 3y(y - 2)(y + 2) \\ = 3y(y + 2)(y - 2)[/tex]

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jordyndyson
jordyndyson jordyndyson
  • 22-05-2021

a^2-b^2=(a+b)(a-b)

a=y b=2

3y(y+2)(y-2)

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