carmens212 carmens212
  • 21-05-2021
  • Mathematics
contestada

A circle with a center at (2,-3) passes through the point (-1,-8). Write the equation of the circle.

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colinspurdle colinspurdle
  • 21-05-2021

Answer: (x - 2)^2 + (y + 3)^2 = 34

Step-by-step explanation:

The basic equation for a circle is

(x - a)^2 + (y - b)^2 = r^2 where (a, b) is the centre of the circle

Using Pythagoras we can find r^2

r^2 = (2 - -1)^2 + (-3 - -8)^2

= 3^2 + 5^2

= 34

So the circle is (x - 2)^2 + (y - -3)^2 = 34

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