biejacerotajunior biejacerotajunior
  • 23-04-2021
  • Mathematics
contestada

what is the value of A when we rewrite (32/5)^-2x as A^x​

Respuesta :

Muscardinus Muscardinus
  • 28-04-2021

Answer:

[tex](\dfrac{25}{1024})^x[/tex]

Step-by-step explanation:

The given expression is :

[tex](\dfrac{32}{5})^{-2x}[/tex]

We need to rewrite it in the form of [tex]A^x[/tex].

We know that, [tex](\dfrac{1}{x})^{-a}=x^a[/tex]

So,

[tex](\dfrac{32}{5})^{-2x}=(\dfrac{5}{32})^{2x}\\\\=(\dfrac{5^2}{32^2})^x\\\\=(\dfrac{25}{1024})^x[/tex]

So, [tex]A=\dfrac{25}{1024}[/tex]. Hence, this is the required solution.

Answer Link
faisyolo faisyolo
  • 12-05-2021

Answer: A = (32/5)^-2

Step-by-step explanation:

Answer Link

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