Answer:
52°
Step-by-step explanation:
BC is the radios so BC is perpendicilar to AC.
mBCA = 90°
<A = 180 - <B - <C
<A = 180 - 38 - 90 = 52°
∠ A = 52°
The angle between the tangent and the radius at the point of contact C is 90°
Then Δ ABC is right.
∠ A = 180° - (90 + 38)° ← sum of angles in a triangle
∠ A = 180° - 128° = 52°
