Roastedham4127 Roastedham4127
  • 24-03-2021
  • Mathematics
contestada

A rectangle has a height of 2x^42x 4 2, x, start superscript, 4, end superscript and a width of x^2+8x+15x 2 +8x+15x, squared, plus, 8, x, plus, 15.

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MrRoyal
MrRoyal MrRoyal
  • 25-03-2021

Question:

A rectangle has a height of 2x^4 and a width of x^2+8x+15. Calculate its area.

Answer:

[tex]Area = 2x^6 + 16x^5 + 30x^4[/tex]

Step-by-step explanation:

Given

[tex]Height = 2x^4[/tex]

[tex]Width = x^2 + 8x + 15[/tex]

Required

Determine the area of the rectangle

This is calculated as:

[tex]Area = Width * Height[/tex]

[tex]Area = (x^2 + 8x + 15) * 2x^4[/tex]

[tex]Area = 2x^6 + 16x^5 + 30x^4[/tex]

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