Answer:
[tex]h^{-1}[/tex] (x) = 2x - 6
Step-by-step explanation:
let y = h(x) and rearrange making x the subject
y = [tex]\frac{1}{2}[/tex] x + 3 ( multiply through by 2 to clear the fraction )
2y = x + 6 ( subtract 6 from both sides )
2y - 6 = x
Change y back into terms of x with x = [tex]h^{-1}[/tex] (x)
[tex]h^{-1}[/tex] (x) = 2x - 6
