Answer:
[tex]m=89.0g[/tex]
Explanation:
Hello!
In this case, since we are given the formula units (molecules) of copper sulfate, it is possible to compute the moles of this compound via the Avogadro's number:
[tex]n=3.36x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules}\\\\n=0.558mol[/tex]
Now, given the molar mass of copper sulfate which is 159.60 g/mol, the required mass in grams turns out:
[tex]m=0.558mol*\frac{159.60g}{1mol}\\\\m=89.0g[/tex]
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