Answer:
[tex]d=7970\ kg/m^3[/tex]
Explanation:
Given that,
The density of iron is 7.97 g/cm³.
We need to find the density in SI unit. The SI unit of density is kg/m³.
We know that,
1 kg = 1000 g
1 m = 100 cm
So,
[tex]7.97\ g/cm^3=7.97 \times \dfrac{(\dfrac{1}{1000})\ kg}{(\dfrac{1}{100}^3)\ m^3}\\\\=7970\ kg/m^3[/tex]
So, the density of the iron is [tex]7970\ kg/m^3[/tex].
