Answer:
m(arc CD) = 122°
Step-by-step explanation:
Since, measure of an arc = 2 × (Angle subtended by the arc at the circumference of the circle)
m(arc CD) = 2[m(∠CBD)]
By triangle sum theorem in ΔBCD,
m∠CBD + m∠BDC + m∠DCB = 180°
m∠CBD + 49° + 70° = 180°
m∠CBD = 180° - 119°
m∠CBD = 61°
Therefore, m(arc CD) = 2 × 61°
m(arc CD) = 122°
