Respuesta :

Answer:

The charge flowing through the filament is 0.08C

Explanation:

[tex]I=20mA = 0.02A\\t= 4s\\[/tex]

Plug your given values into the charge and current formula:

[tex]I=\frac{Q}{t} \\Q=I*t\\Q= (0.02A)(4s)\\Q= 0.08C[/tex]