Answer:
[tex]\boxed{\bold{\left(2x-1\right)\left(4x^2+2x+1\right)}}[/tex]
Explanation:
Apply difference of cubes formula: [tex]\bold{x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)}[/tex]
[tex]\bold{\left(2x\right)^3-1^3=\left(2x-1\right)\left(2^2x^2+2x+1\right)}[/tex]
= [tex]\bold{\left(2x-1\right)\left(2^2x^2+2x+1\right)}[/tex]
2² = 4
[tex]\boxed{\bold{\left(2x-1\right)\left(4x^2+2x+1\right)}}[/tex]
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