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Solve the problem by making up an equation. A man could arrive on time for an appointment if he drove the car at 40 mph; however, since he left the house 15 minutes late, he drove the car at 50 mph and arrive 3 minutes early for the appointment. How far from his house was his appointment?
And if the appointment is x miles away from man's house the equation is

Respuesta :

Answer:

40 miles

Step-by-step explanation:

Since we are dealing in mph, change the minutes to hr

15 min: 15/60 = .25 hrs

3 min: 3/60 = .05 hrs

:

Let t = his normal drive time to work in hrs

then

40t = the distance to work

 

Write a distance equation; dist = speed * time

50(t-.25 + .05) = 40t

50(t - .20) = 40t

50t - 10 = 40t

50t - 40t = 10

10t = 10

t = 1 hr normal time to work

therefore

40(1) = 40 mi to work

:

:

Confirm this by finding the dist when he went 50 mph for 48 min (.8hrs)

50(1-.25+.05) = 50(.8) = 40 mi also

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