Answer:
[tex] { (\frac{2 {p}^{3} }{ {q}^{2} }) }^{( - 4)} = \frac{{2}^{(-4)} {p}^{(3 \times ( - 4))} }{ {q}^{(2 \times ( - 4))} } = \frac{ {p}^{ (- 12)} }{16 {q}^{( - 8)} }=\boxed{\frac{ {q}^{8} }{ 16{p}^{12} }} \\ [/tex]
q⁸/16p¹² is the right answer.
