ecdsbairbondez ecdsbairbondez
  • 23-10-2016
  • Chemistry
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What is the ph of 2.34 * 10^-5 naoh solution?

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Willchemistry
Willchemistry Willchemistry
  • 30-10-2016
NaOH = Na⁺  + OH⁻

pOH = - log [ OH⁻ ]

pOH = - log [ 2.34x10⁻⁵ ]

pOH = 4.63

Therefore:

pH + pOH = 14

pH + 4.63 = 14

pH = 14 - 4.63

pH = 9.37
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