How do you solve log_8 5 -log_8(x-6)=1?

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23-10-2016
Mathematics

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How do you solve log_8 5 -log_8(x-6)=1?

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Аноним Аноним · Answer 1 · 2016-10-23T13:15:14+02:00

Аноним Аноним

23-10-2016

log₈ 5-log₈ (x-6)=1

1)
log_a b- log_a c=log_a b/c

log₈ 5/(x-6)=1

2)
log_a b=c ⇔ a^c=b

log₈ 5/(x-6)=1 ⇔ 8¹= 5/(x-6)
8(x-6)=5
8x-48=5
8x=5+48
8x=53
x=53/8

Answer: x=53/8

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