Proof:
In [tex]\triangle KSP[/tex] and [tex]\triangle NSM[/tex]:
[tex]\overline K \overline S \cong \overline N \overline S[/tex] (given)
[tex]\angle KSP = \angle NSM[/tex] (vertically opposite angles are equal)
[tex]\overline S \overline P = \overline S \overline M[/tex] (given)
[tex]\therefore \triangle KSP \cong \triangle NSM (SAS)[/tex]
Hope this helps :)
