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21-12-2020
Mathematics

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Find the sum of the first 38 terms of the following series, to the nearest integer. 10, 14, 18,...

Respuesta :

kevxngyn kevxngyn

21-12-2020

A(n) = A(1) + (n - 1)d
A(38) = 10 + (38 - 1)4
A(38) = 158
The 38th term is 158.
S(n) = n/2 (A(1) + A(n)
S(38) = 38/2 (10 + 38)
S(38) = 19 (48)
S(38) = 912
The sum of the first 38 terms is 912.

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