Answer:
V = 192 kV
Explanation:
Given that,
Charge, [tex]q=6.4\times 10^{-6}\ C[/tex]
Distance, r = 0.3 m
We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :
[tex]V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6.4\times 10^{-6}}{0.3}\\\\V=192000\ V\\\\V=192\ kV[/tex]
So, the required electric potential is 192 kV.
