Answer:
V₂ = 4.4 L
Explanation:
Given data:
Initial volume = 5.5 L
Initial pressure = 650 mmHg (650/760 =0.86 atm)
Initial temperature = 20 °C (20 +273 = 293 K)
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/T₁ P₂
V₂ = 0.86 atm× 5.5 L × 273 K / 293 k × 1 atm
V₂ = 1291.29 atm.K.L / 293 k.atm
V₂ = 4.4 L
