Answer:
A is two; B is nine; C is one
Good Luck!
a) C has to be either one or zero (but I'm assuming the solution you're wanting is when C=1). This is because A+B + Whatever is carried can only be a number 0-19, meaning only a 1 can be carried to the third column.
b) if C is 1, then in the ones place, B+A must = 11
c) if the carried 1 + a + b = 10 + a, then a can be substituted and we find that b = 9; and a =2
