Answer:
Step-by-step explanation:
[tex]\frac{1}{3} (x+3)+4=-4+\frac{2}{3} x\\multiply~by~3\\x+3+12=-12+2x\\x-2x=-12-3-12\\-x=-27\\or~x=27\\[/tex]
or if it is
[tex]\frac{1}{3} (x+3)+4=-4+\frac{2}{3x}\\ multiply~by~3x\\x(x+3)+12x=-12x+2\\x^2+3x+12x+12x=2\\x^2+27x-2=0\\x=\frac{-27 \pm \sqrt{(27)^2-4*1*-2} }{2*1} \\or~x=\frac{-27 \pm \sqrt{729+8} }{2} \\or~x=\frac{-27 \pm\sqrt{737} }{2}[/tex]
