Respuesta :

Hrishii

Answer:

See Explanation

Step-by-step explanation:

[tex] In \: \odot M, \: \overline{MA} \: bisects \: \overline {BC}\\... (given) \\\\

\therefore \overline{MN} \: bisects \: \overline {BC}\\... (\because B-N-C) \\\\

\therefore BN \cong NC... (1)\\\\

In\: \triangle BMN \:\&\:\triangle CMN\\\\

BM\cong CM\\ (radii \: of \: same \: circle) \\\\

MN\cong MN\\ (common \:side) \\\\

BN \cong NC\\ (from\:1)\\\\

\triangle BMN \:\cong\:\triangle CMN\\.. (by\: SSS\: postulate) \\\\

\therefore \angle B\cong \angle C.. (CACT) [/tex]

Otras preguntas