Answer:
The three rules that we have are:
[tex]x^a*x^b = x^{a + b}[/tex]
[tex]\frac{x^a}{x^b} = x^{a - b}[/tex]
[tex](x^a)^b = x^{a*b}[/tex]
Then let's solve the problems:
A) 2^4 = 2^(2*2) = (2^2)^2 = 4^2 = 16.
B) 3^0 = 3^(a - a) = 3^a/3^a = 1. (for any real number a)
From this we can conclude that the power 0 of any number is equal to 1.
C) 4^6*4^(-3) = 4^(6 - 3) = 4^3 = 64
D) (2^3)^2 = 2^(3*2) = 2^6 = 64
