Answer:
C₃₆H₆₂O₃₁
Explanation:
Hello,
In this case, since glucose has a molecular formula of C₆H₁₂O₆ and two hydrogen atoms and one oxygen atom are lost per additional glucose, two glucoses would be C₁₂H₂₂O₁₁, three glucoses would be C₁₈H₃₂O₁₆, four glucoses would be C₂₄H₄₂O₂₁, five would be C₃₀H₅₂O₂₆ and therefore six glucose molecules would have molecular formula of C₃₆H₆₂O₃₁.
Best regards.
