Answer:
33600 J
Explanation:
From the question,
ΔH = cm(t₂-t₁)..................... Equation 1
Where, ΔH = Enthalpy change of water, c = specific heat capacity of water, m = mass of water, t₂ = Final temperature of water, t₁ = Initial temperature of water
Given: c = 4200 J/kg.°C, m = 100 g = 0.1 kg, t₂ = 50°C, t₁ = -30°C
Substitute these values into equation 1
ΔH = 4200(0.1)(50+30)
ΔH = 420(80)
ΔH = 33600 J
