aydenav4405 aydenav4405
  • 22-07-2020
  • Mathematics
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jimthompson5910 jimthompson5910
  • 22-07-2020

Answer: Choice D.  [tex]f^{-1}(x) = \frac{6x+2}{3}[/tex]

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The idea is that you replace f(x) with y, swap x and y, then solve for y to get the inverse.

[tex]f(x) = \frac{3x-2}{6}\\\\y = \frac{3x-2}{6}\\\\x = \frac{3y-2}{6}\\\\6x = 3y-2\\\\3y-2 = 6x\\\\3y = 6x+2\\\\y = \frac{6x+2}{3}\\\\f^{-1}(x) = \frac{6x+2}{3}\\\\[/tex]

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