Answer:
The gradient of the curve at x = 2 is 9.
Explanation:
Given that the 1st derivative of differentiation is gradient. So you have to differentiate the equation first :
[tex]y = {x}^{2} + 5x - 3[/tex]
[tex] \frac{dy}{dx} = 2x + 5[/tex]
Next, you have to substitute x = 2 into the differentiated form of equation :
[tex]let \: x = 2[/tex]
[tex] \frac{dy}{dx} = 2(2) + 5 = 4 + 5 = 9[/tex]
