mohammedarif1972 mohammedarif1972
  • 22-06-2020
  • Mathematics
contestada

Please answer my question if you answer it I will surely mark you as the brainliest and if you answer it you will get 30 points and if you answer it I will rate you

Please answer my question if you answer it I will surely mark you as the brainliest and if you answer it you will get 30 points and if you answer it I will rate class=

Respuesta :

devishri1977
devishri1977 devishri1977
  • 22-06-2020

Answer:

Step-by-step explanation:

[tex]1) \frac{tan A + Sin A}{tan A - Sin A}=\frac{\frac{sin A}{cos A}+sinA}{\frac{sinA}{cos A}-sin A}\\\\=\frac{\frac{sin A + Sin A CosA}{Cos A}}{\frac{sinA-sinAcosA}{cosA}}\\\\=\frac{sin A + Sin A CosA}{Cos A}*\frac{cosA}{sinA-sinAcosA}\\\\=\frac{sinA+sinAcosA}{sinA-sinAcosA}\\\\=\frac{sinA(1+cosA)}{SinA(1-cosA)}\\\\\frac{1+cosA}{1-cosA}\\\\=\frac{1+\frac{1}{secA}}{1-\frac{1}{secA}}\\\\=\frac{\frac{secA+1}{secA}}{\frac{secA-1}{secA}}\\\\=\frac{secA+1}{secA-1}[/tex]

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