Answer:
[tex]x=0, \dfrac{1}{2}, -\dfrac{1}{2}[/tex]
Step-by-step explanation:
[tex]4x^3-x=0 \\\\x(4x^2-1)=0 \\\\x(2x-1)(2x+1)=0 \\\\x=0, \dfrac{1}{2}, -\dfrac{1}{2}[/tex]
Hope this helps!
x=0 x = 1/2 x = -1/2
4x^3 - x=0
Factor out an x
x(4x^2 -1) =0
Factor inside the parentheses ( difference of squares a^2 -b^2 = (a-b)(a+b))
x (2x-1)(2x+1) =0
Using the zero product property
x=0 2x-1 =0 2x+1 =0
x =0 2x=1 2x = -1
