Answer: - 1023
Step-by-step explanation:
Given
Sequence is [tex]3+(-6)+12+(-24)...[/tex]
The following sequence is a geometric series with common ratio [tex]r=-2[/tex]
first term [tex]a=3[/tex]
[tex]Sum=\sum _{i=1}^{n}ar^{n-1}=\dfrac{a(1-r^n)}{1-r}[/tex]
[tex]Sum=\sum _{i=1}^{n}3(-2)^{n-1}=\dfrac{3(1-(2)^10)}{1+2}[/tex]
[tex]Sum=\sum _{i=1}^{n}3(-2)^{n-1}=-1023[/tex]
