kaitlynhileman728
kaitlynhileman728 kaitlynhileman728
  • 22-05-2020
  • Physics
contestada

If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do

Respuesta :

temdan2001
temdan2001 temdan2001
  • 29-05-2020

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

U = 11.5m/s

V = 3.33m/s

how much work did friction do

Work done = Force × distance

Work done = Ma × distance

But acceleration a = V/t

Work done = M × V/t × d

Work done = M × V × d/t

Where d/t = velocity

Therefore,

Work done = M × U × V

Work done = 42 × 11.5 × 3.33

Work done = 1608.39 J

Answer Link

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