Answer:
[tex]-2x^{5}y^{2}\sqrt[3]{y^{2}}[/tex]
Step-by-step explanation:
[tex]\sqrt[3]{-8x^{15}y^{8}} = -2x^{5}\sqrt[3]{y^{6}y^{2}} =-2x^{5}y^{2}\sqrt[3]{y^{2}}[/tex]
