bigsis2kaden
bigsis2kaden
25-08-2016
Mathematics
contestada
tan(x)+tan(y)=sin(x+y)/cos(x)cos(y)
Respuesta :
Panoyin
Panoyin
26-08-2016
[tex]tan(x) + tan(y) = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x)}{cos(x)} + \frac{sin(y)}{cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x)cos(y)}{cos(x)cos(y)} + \frac{sin(y)cos(x)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x)cos(y) + sin(y)cos(x)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
[tex]\frac{sin(x + y)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}[/tex]
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