Answer:
1001
Step-by-step explanation:
Note that n! = n(n - 1)(n - 2).. × 3 × 2 × 1
Given
[tex]\frac{14!}{4!10!}[/tex]
14! = 14(13)(12)(11)(10)(9)(8)(7)(6)...
10! = 10(9)(8)(7)(6).....
Cancel the factors of 14! with those of 10!, leaving
= [tex]\frac{14(13)(12)(11)}{4(3)(2)}[/tex]
= [tex]\frac{24024}{24}[/tex]
= 1001
