hejdndj hejdndj

25-04-2020
Chemistry

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How many moles of C12H22O11C12H22O11are needed to prepare 2.50 L of 0.300 M solution?

Respuesta :

sakyiamahchristiana sakyiamahchristiana

25-04-2020

Answer:

0.75 mol

Explanation:

concentration=mole/volume

c×v=n

volume=2.50l=2.50dm³

0.300×2.50=0.75mol

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