gilchristdeandre gilchristdeandre

25-04-2020
Mathematics

contestada

Determine a, given that A = 63°, C = 49°, and c = 3.

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chudung1976 chudung1976

26-04-2020

Answer:

[tex]\frac{c.sinA}{sinC} =\frac{3.sin63^{0} }{sin49^{0} } =3.542[/tex]

Step-by-step explanation:

+ We use this theorem: a/sinA=c/sinC for a triangle.

+ Then \frac{c.sinA}{sinC} =\frac{3.sin63^{0} }{sin49^{0} } =3.542

Hope you understand.

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