ariidarealist ariidarealist
  • 22-04-2020
  • Mathematics
contestada

uuuuLITUNCION
Given the function f(x) = -2x2 + 3 over the closed
interval [-1, 2], what are the extreme values?
Minimum:
Maximum:

Respuesta :

ghanami
ghanami ghanami
  • 22-04-2020

Answer:

Step-by-step explanation:

hello :

f(x) = -2x²+3

in : [-1, 2]   f'(x) = - 4x

f'(x) = 0  means : -4x=0   so : x=0

f(0) = -2(0)²+3 = 3 (Maximum:) because : a= -2 and a<0

in :  [-1, 0]   f is  crasing

in :  [-1, 2]   f is  decrasing

Answer Link
ashleyalvarez345 ashleyalvarez345
  • 02-05-2020

Answer:

1.-5

2.3

Step-by-step explanation:

just did it

Answer Link

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