Answer: 0
Step-by-step explanation:
[tex]-\frac{2}{3}(x+5)+4(x+5)-\frac{10}{3}(x+5) = ?[/tex]
[tex]-\frac{2}{3}x-\frac{10}{3}x+4x+20-\frac{10}{3}x-\frac{50}{3} = ?[/tex]
[tex](-\frac{2}{3}x+4x -\frac{10}{3}x) +(-\frac{10}{3}+20-\frac{50}{3})=?[/tex]
[tex](-\frac{12}{3}x+4x)+(-\frac{60}{3}+20)=?\\ (-4x+4x)+(-20+20)=?\\0+0=0[/tex]
