Answer:
2,-1 and -3/2
Step-by-step explanation:
If one zero of polynom is 2 then we can divide our polinom with (x-2), and we will get
(2x^3+x^2-7x-6)/(x-2)=2x^2+5x+3
Now we have ti find zeros for 2x^2+5x+3
3 is without x so we have factors:
1,-1,3,-3, 1/2,-1/2,3/2,-3/2.
Chack does any of them zero.
For -1 we have:
2(-1)^2+5(-1)+3=2-5+3=0
So -1 is zero of the polynom.
Now divide again with (x+1) wi get:
(2x^2+5x+3)/(x+1)=2x+3
2x+3=0 if x=-3/2
So we have all zeros:
2,-1 and -3/2
