Answer:
Step-by-step explanation:
Similar trianles corresponding side are in ratio
[tex]\frac{PQ}{DE}=\frac{QR}{FE}\\\\\frac{6}{x}=\frac{4}{10}\\\\6*10=4*x\\\\x=\frac{6*10}{4}\\\\x=3*5=15[/tex]
[tex]\frac{PR}{DF}=\frac{QR}{EF}\\\\\frac{y}{20}=\frac{4}{10}\\\\y*10=20*4\\\\y=\frac{80}{10}\\\\y=8[/tex]
