animallover18
animallover18 animallover18
  • 25-03-2020
  • Mathematics
contestada

Please see attachment for the question.

Please see attachment for the question class=

Respuesta :

Wallind11
Wallind11 Wallind11
  • 25-03-2020

Step-by-step explanation:

[tex] \frac{10 {x}^{3} - 12 {x}^{2} + 6x - 7 }{ - 14 {x}^{2} - 1 } [/tex]

-14x²-1≠0

x²≠ -1/14

Option C

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